List All Objects and Indexes in a Filegroup or Partition

By Lori Brown | Intermediate

Nov 17

— by Lori Brown @SQLSupahStah

One of my clients has a rather large database with multiple filegroups and multiple database files in them. I happened to notice that a specific drive that is occupied by 2 specific files that are supposed to hold indexes is getting utilized at a much higher rate than any of the other files. The index file group has 8 files in it. I was anticipating gathering some performance data to try to figure out what indexes are located on those specific files and needed a way to figure that out. My searching for a script led me to TechNet where there are a bunch of scripts that are freely downloadable. The one I needed came Olaf Helper. I added a join on the database files so that I could see what file they are on and filter on that.

Since I need to join my query to the actual database files, I needed to figure out what the file_id was for the specific files that I am interested in.

SELECT * FROM sys.database_files

This is a very modified output so you can see the different filegroups and the files in them.


Checking the data in sys.database files will give you the answer.

Anyway, put it all together and mine looks like this:

SELECT AS DataSpaceName


,AU.type_desc AS AllocationDesc

,AU.total_pages / 128 AS TotalSizeMB

,AU.used_pages / 128 AS UsedSizeMB

,AU.data_pages / 128 AS DataSizeMB

, AS SchemaName

,OBJ.type_desc AS ObjectType

, AS ObjectName

,IDX.type_desc AS IndexType

, AS IndexName

FROM sys.data_spaces AS DS

INNER JOIN sys.allocation_units AS AU

ON DS.data_space_id = AU.data_space_id

INNER JOIN sys.partitions AS PA

ON (AU.type IN (1, 3)

AND AU.container_id = PA.hobt_id)


(AU.type = 2

AND AU.container_id = PA.partition_id)

JOIN sys.database_files f

on AU.data_space_id = f.data_space_id

INNER JOIN sys.objects AS OBJ

ON PA.object_id = OBJ.object_id

INNER JOIN sys.schemas AS SCH

ON OBJ.schema_id = SCH.schema_id

LEFT JOIN sys.indexes AS IDX

ON PA.object_id = IDX.object_id

AND PA.index_id = IDX.index_id

WHERE f.file_id IN (13,14) AND AU.total_pages > 0 — Look at specific files, could also filter on file group

ORDER BY AU.total_pages desc — Order by size





The output looks like this…I sorted on size but left the columns needed to sort by name:


Now I am ready to collect performance data to see what stressful queries are using the indexes located on these files.

I don’t have the results from the performance data just yet but will likely follow up later on putting all the pieces together to solve this very specific problem.

For more information about blog posts, concepts and definitions, further explanations, or questions you may have…please contact us at We will be happy to help! Leave a comment and feel free to track back to us. Visit us at!



About the Author

Lori is an avid runner, cross fitter and SQL enthusiast. She has been working for SQLRX for 15 years and has been working with SQL in general for 25 years. Yup...she is an old hand at this stuff.